.
rpasken@eas.slu.edu , You have made comments that Momentum is not Conserved in my PAPER. It is not
rpasken@eas.slu.edu , You have made comments that Momentum is not
Conserved in my PAPER. It is not CORRECT. It is explained in 100 Years of E=mc2rpasken@eas.slu.eduRobert Pasken
Department of Earth and AtmosphericSciences
Saint Louis University
3507 Laclede Avenue
St.Louis, MO 63103See how Momentum is conserved in my paper. All references are given in the end. Part I General meaning , explained in 11th class Physics.The law of momentum conservation,
* In an isolated system, the momentum of system must be conserved.*
Mathematically implies that Initial Momentum = Final Momentum
mu=mv (1)
As mass remains same in classical mechanics.
So u=v
which is Newton’s First law of motion.
Application of momentum conservation.
When body emits energy ( in this cases light energy)
then it recoils .Thus it is used to calculate the velocity of recoil.
It can be applied to following two cases.
------ Light bullet fired from TOY Gun, system remains at rest. ( body does not recoil with noticeable velocity, it tends to recoil)
The velocity cam be calculated but may be of the order of
1/100000000000000000000000000000000000 m/s or 10-^40m/s
This case resembles with Einstein’s two waves of equal energy emitted in opposite directions.-----Shot fired from gun, gun moves backward.
the velocity can be calculated from conservation of momentum i.e.
initial momentum =final momentum
Vrecoil = mv/M ~ 5m/s (say)
Thus after emission of energy BODY MAY REMAIN AT REST OR MOVE, the Momentum is Conserved. It is basic physics of 11th standard.
If some one does not want to understand this then it his problem.Einstein did all calculation under Classical conditions of velocity (v <<c, her v is relative velocity between two systems i.e. system in which body emits light and second system in which energy is measured. Part II
The law of conservation of momentum is obeyed in my paper.https://www.novapublishers.com/catalog /product_info.php?cPath=23_48_324&products_id=4554When two waves are emitted. The body recoils with velocity v , with magnitude of the order of 10^-32 m/s i.e.
V (recoil)=1/10000000000000000000000000000000000000000000000000It can be easily calculated. When two waves of different energies are emitted. If body emits two light waves of slightly different energies i.e. 0.5001L and 0.4999L (Einstein has used light waves of energy 0.5L and 0.5L) in opposite directions. Now using the law of conservation of momentum, it can be easily justified that in this case body remains at rest.
Let the body of mass 10kg emits light energy in two waves in visible region equal to 7.9512×10^-19 J, this energy corresponds to TWO light waves in visible region having wavelength 5000ºA or energy, 2hc/λ or 7.9512×10^-19 J.
Let towards the observer the body emits light energy 0.5001L i.e. 3.97639512×10^-19 J i.e. will have momentum ( p1 = E/c) 1.32546504×10^-27 m/s.
Secondly, the body emits light wave of energy 0.4999L i.e. 3.97480488×10^-19 J, away from the observer (φ= 180º) i.e. will have momentum ( p2 = E/c) 1.32493496×10^-27 m/s. Let us assume that when the body emits light waves of energy and moves (if it actually does) with velocity Vb , then according to law of conservation of momentum we get
0 = p1 +p2 +MbVb or Vb = -(p1 +p2) /Mb = –5.3×10^-32 m/s (2) 0 = p1 +p2 +MbVb or Vb = -(p1 +p2) /Mb = –5.3×10^-32 m/s (3)
Thus conservation of momentum requires that body should move with velocity –5.3×10^-32 m/s opposite to observer. Thus body will tend to move with velocity 5.3×10^-32 m/s ( away from the observer) which is immeasurably small by all means, hence the body remains at rest. Due to this uniform relative velocity v of the system (ξ, η, ζ ) will not change, if body moves then v will vary accordingly. =========Einstein’s Sep 1905 paper===========The first and basic equation in Einstein’spaper is l* = l{1 – v/c cos φ } /√<1 – v2 /c2> (1) In eq.(1) v is the relative velocity between light emitting body and the measuring system i.e. system (ξ, η, ζ ). If body moves after emission with velocity v’ away from the observer, then relative velocity will be v+v’ (say V). Thus in this case eq.(1) becomesℓ* = ℓ{1 – (v+v’) cos φ/c } /√<1 – (v+v’)2 /c2> (1a)
The rest of the calculations remain the same. Thus Einstein’s derivation is also valid if the body moves, Einstein has considered the simplest case when velocity v’ is zero (V= v+v’ =v), which is special case. Also experimentally the law of inter conversion of mass energy holds good in all possible cases.Hence you cannot say that LAW OF CONSERVATION OF MOEMTUM IS NOT TAKEN IN€COUNT IN MY PAPER. It is your MISPERCEPTION.AJAY SHARMA 2ND Oct 2006References of Einstein’s work
. A.Einstein, Annalen der Physik 18 (1905) 639-641.
. DOES THE INERTIA OF A BODY DEPEND
UPON ITS ENERGY-CONTENT?Weblink is Einstein’s 27 Sep 1905 paper available at http://www.fourmilab.ch/etexts/einstein/E_mc2/www/
PartII
References of Ajay Sharma’s work My work is available atA. Sharma, Physics Essays, 17 (2004) 195-222.”The Origin of Generalized Mass-Energy Equation DE = Ac2 DM; and its applications in General physics and Cosmology”. http://www.burningbrain.org/pdf/ajaysharma_einstein.pdfFor detailshttps://www.novapublishers.com/catalo g/product_info.php?cPath=23_48_324&products_id=4554
Published: October 03, 2006